mình xin lỗi!!!a=x nha!!!

\(1+\left(-2\right)+3+\left(-4\right)+5+...+77+\left(-78\right)+79+\left(-80\right)\)

\(=\left[1+\left(-2\right)\right]+\left[3+\left(-4\right)\right]+\left[5+\left(-6\right)\right]+...+\left[77+\left(-78\right)\right]+\left[79+\left(-80\right)\right]\)

\(=-1+\left(-1\right)+\left(-1\right)+...+\left(-1\right)\)

Từ 1 -> 80 có số số hạng là: (80-1):1+1=80 số hạng

=> Có 80:2=40 số -1

\(=-1\cdot40=-40\)

Đặt: \(A=1+\left(-2\right)+3+\left(-4\right)+...+77+\left(-78\right)+79+\left(-80\right)\)

\(\Rightarrow A=1-2+3-4+...+77-78+79-80\)

\(\Rightarrow A=-1-1-...-1-1\)            (     \(40\)cặp)

\(\Rightarrow A=-1\times40=-41\)

1+(-2)+3+(-4)+5+...+77+(-78)+79+(-80)

=(2-1)+(4-3)+(6-5)+...+(78-77)+(80-79)

=1+1+1+...+1+1

=40.1

=40

=(2^78+79+80):(2^77+76+75)

=2²³⁷:2²²⁸

=2^237-228

=2⁹

=512

Bài 1.          n;    1;-1;-2;-4;-5;-7

Bài 2 =-80

\(a;\frac{2^{78}+2^{79}+2^{80}}{2^{77}+2^{76}+2^{75}}=\frac{2^{78}\left(1+2+2^2\right)}{2^{75}\left(1+2+2^2\right)}=2^3=8\)

b) \(\frac{5^{56}+5^7}{5^{49}+1}=\frac{5^7\left(5^{49}+1\right)}{5^{49}+1}=5^7\)

\(\left(2^{78}+2^{79}+2^{80}\right):\left(2^{77}+2^{76}+2^{75}\right)=\left(2^{78}.7\right):\left(2^{75}.7\right)=2^{78}:2^{75}=8\)

9: \(=1-\dfrac{1}{99}+1-\dfrac{1}{100}+\dfrac{100}{101}\cdot\dfrac{1-4+3}{12}=2-\dfrac{199}{9900}=\dfrac{19601}{9900}\)

10: \(=\left(\dfrac{78}{79}+\dfrac{79}{80}+\dfrac{80}{81}\right)\cdot\dfrac{6+5+9-20}{30}=0\)